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x^2-2x=11.25=0
We move all terms to the left:
x^2-2x-(11.25)=0
We add all the numbers together, and all the variables
x^2-2x-11.25=0
a = 1; b = -2; c = -11.25;
Δ = b2-4ac
Δ = -22-4·1·(-11.25)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-7}{2*1}=\frac{-5}{2} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+7}{2*1}=\frac{9}{2} =4+1/2 $
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